Yes, but be careful. Actually, never call a virtual function in ctor or dtor.
@ the answer form the author of C++
@ the answer form the author of C++
@http://hilite.me/
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 | #include <iostream> using namespace std; class Shape { public: virtual void draw() { cout << "draw a Shape." << endl; } }; class Circle : public Shape { public: void draw() { cout << "draw a Circle." << endl; } }; class Base { public: Base() { cout << "Base()" <<endl; f(); Shape* shape = new Circle; shape->draw(); } virtual void f() { cout << "Base::f()" << endl; } }; class Derive : public Base { public: Derive() { cout << "Derive()" << endl; } void f() { cout << "Derive::f()" << endl; } }; int main() { Base* b = new Derive; return 0; } |
Base::f()
draw a Circle.
Derive()
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