Thursday, June 18, 2015

Install GDB on MAC with Homebrew

1. install Homebrew
@ http://brew.sh/

2. install GDB with Homebrew

$ brew tap homebrew/dupes
$ brew install gdb

3. codesign gdb

@http://ntraft.com/installing-gdb-on-os-x-mavericks/

Friday, June 12, 2015

Calling another ctor in one ctor


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#include <iostream>
using namespace std;


class Widget {
public:
    Widget(int n) {
        data = n;
        cout <<"Widget(int n): this=" <<this <<endl;
    }

    Widget() {
        cout<<"Widget(): this=" <<this <<endl;
        Widget(8888);
    }

    ~Widget() {
        cout<<"~Widget(): this=" <<this <<" data=" <<data <<endl;
    }


    void print() const  {
        cout <<"print(): this=" <<this <<" data=:"<<data <<endl;
    }

private:
    int data;
};


int main()
{
    Widget a;
    a.print();
    return 0;
}

output:

Widget(): this=0x7fff556f9c08
Widget(int n): this=0x7fff556f9b90
~Widget(): this=0x7fff556f9b90 data=8888
print(): this=0x7fff556f9c08 data=:1794977846
~Widget(): this=0x7fff556f9c08 data=1794977846

Can I call a virtual function from ctor in C++?


Yes, but be careful. Actually, never call a virtual function in ctor or dtor.
the answer form the author of C++

@http://hilite.me/

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#include <iostream>

using namespace std;

class Shape {
public:
    virtual void draw() {
        cout << "draw a Shape." << endl;
    }
};

class Circle : public Shape {
public:
    void draw() {
        cout << "draw a Circle." << endl;
    }
};


class Base {
public:
    Base() {
        cout << "Base()" <<endl;

        f();
        
        Shape* shape = new Circle;
        shape->draw();
    }

    virtual void f() {
        cout << "Base::f()" << endl;
    }
};

class Derive : public Base {
public:
    Derive() {
        cout << "Derive()" << endl;
    }

    void f() {
        cout << "Derive::f()" << endl;
    }
};


int main()
{
    Base* b = new Derive;
    
    return 0;
}

Base::f()
draw a Circle.
Derive()

Saturday, June 6, 2015

No virtual ctor in C++

We can't inherit constructors, so there is no need for them to be virtual.

A vtable is made for each class having one or more 'virtual functions'. Whenever an object is created of such class, it contains a 'virtual-pointer' which  points to the base of corresponding vtable. Whenever there is a virtual function call, the vtable is used to resolve to the function address.

Ctor can not be virtual, because when ctor of a class is executed there is NO vtable in the memory, meaning no virtual pointer defined yet. Hence the ctor should always be non-virtual.

If you think logically about how ctor works and what the meaning/usage of a virtual function is in C++ then you will realize that a virtual ctor would be meaningless in C++. Declaring something virtual in C++ means that it can be overridden by a sub-class of the current class; however the ctor is called when the object is created, at that time you can NOT be creating a sub-class of the class that you must be creating, so there would never be any need to declare a ctor virtual.

the answer from the author of C++


const data members in C++

1. Constant member of an Object:
the constant member gets initialized in the initialization list:

class A
{
  A(
int size);  // 
  const int SIZE ;  
};
A::A(
int size) : SIZE(size)  
{

}
A  a(
100); // value of SIZE in object a is : 100
A  b(200); // value of SIZE in object a is : 200 

The whole idea for a constant is that you can initialize it but you cannot change it.

2. Const member of a Class:
2.1 using enum (int only)
class A
{
  
enum { SIZE1 = 100, SIZE2 = 200}; // enum const member
  int array1[SIZE1];
  
int array2[SIZE2];
}; 

2.2 using static

class A
{

  static const int a = 100;
  static const pi = 3.1415926;

};